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The Problem and Its Status

The binary Goldbach conjecture: precise statement, computational record, and the strongest results known as of mid-2026.

Conjecture

Status as of July 2026. The binary Goldbach conjecture remains open: it is neither proved nor refuted. Every even integer up to 41018 is verified to be a sum of two primes (Oliveira e Silva, Herzog, Pardi, Math. Comp. 83, 2014) — an empirical fact, not a proof. The strongest unconditional partial result remains of Chen type: every sufficiently large even N is the sum of a prime and a number with at most two prime factors (Chen, 1973). The best published exceptional-set bound is E(X)X0.879 (Lu, 2010); stronger bounds exist as unreviewed preprints and are labeled as such below.

What this site does not claim

No proof of the conjecture, and no claim of being close to one. The results of this project are partial: corollaries derived from published work, one theorem conditional on the (widely disbelieved) Siegel-zero hypothesis, and machine-checked combinatorial facts — none of which advances the conjecture itself. The approaches studied here map the known impossibility frontier — the parity barrier — rather than bypass it; every route that once seemed to bypass it has been refuted, and the refutations are published on this site.

Statement

On 7 June 1742, Christian Goldbach, then working in Moscow, wrote a letter to Leonhard Euler. In the ensuing correspondence the following assertion took shape; it has remained open for almost three centuries.

Binary (strong) Goldbach conjecture. Every even integer N>2 is the sum of two primes:

N=p+q,p,q prime.

The conjecture is unproved and unrefuted. Everything listed on this page is a partial result, an approximation, or a conditional theorem; none of it constitutes a proof.

The natural quantitative measure of the problem is the representation counting function

r(N)=#{(p,q):p+q=N, p,q prime}.

The conjecture is equivalent to the assertion that r(N)1 for every even N4. The Hardy–Littlewood circle method predicts an asymptotic formula for r(N) whose leading factor is the so-called singular series:

S(N)=2C2pNp>2p1p2,C2=p>2(11(p1)2)0.6601

The Hardy–Littlewood heuristic asserts that r(N)S(N)N(lnN)2. Note that S(N)>0 for even N: the heuristic predicts an abundance of representations. What no one has managed to do is turn that heuristic into a proof.

Computational verification

Direct computation has verified the conjecture over an enormous initial range. The record is due to Oliveira e Silva, Herzog, and Pardi: Empirical observationverified up to 41018

T. Oliveira e Silva, S. Herzog, S. Pardi, “Empirical verification of the even Goldbach conjecture and computation of prime gaps up to 41018”, Mathematics of Computation 83 (2014), 2033–2060. Every even integer up to 41018 is indeed a sum of two primes. Published article: doi:10.1090/S0025-5718-2013-02787-1; the project page describing the computation, formerly at sweet.ua.pt, is preserved in the Internet Archive.

Computational verification is not a proof: it covers a finite — albeit enormous — range and says nothing about integers beyond it.

Chen’s theorem and the “(1 + a)” scale

The principal unconditional result of the twentieth century on the Goldbach problem is due to Chen Jingrun (announced 1966, full proof published 1973): Theorem

Chen’s theorem. Every sufficiently large even integer N has a representation

N=p+P2,

where p is prime and P2 is a product of at most two primes (an “almost prime”).

Progress is conveniently measured on the “(1 + a)” scale: the assertion (1 + a) means a representation N=p+Pa, where the second summand has at most a prime factors.

For non-integer a we follow the sources’ convention: (1 + a) means N=p+rq with r=1 or r prime, rqa1 — a size condition on the correction factor, comparable to but not identical with the almost-prime count at integer a. The fractional scale is a bookkeeping convention, not a metric of distance to (1 + 1).

AssertionStatementStatus
(1 + 2)N=p+P2 for all sufficiently large even NTheoremChen’s theorem, 1966/1973
(1 + 1)N=p+q — both summands primeConjectureGoldbach conjecture

For half a century, Chen’s theorem remained unsurpassed on this scale.

The current frontier: a claimed (1 + 1.9)

Li & Liu, preprint arXiv:2606.05224 (2026): Preprint, not peer-reviewedv1

The result claimed in the preprint: every sufficiently large even integer N has representations of the form

N=p+rq,r=1 or r prime,rq0.9,

where p and q are prime. The case r=1 is Goldbach itself; the claim, however, allows a “correction factor” r bounded by q0.9. This would advance beyond Chen’s (1 + 2), but it is not a proof of the Goldbach conjecture: the argument neither isolates the representations with r=1 nor guarantees that any occur.

Status: not refereed. The statement above is reported from version v1 of the preprint. Until independent review is complete, it should be regarded as preliminary, not as an established theorem.

The exceptional set

A different approach is to bound how many even integers could be counterexamples. Denote by E(X) the number of even NX that are not a sum of two primes. The Goldbach conjecture is equivalent to E(X)=0 for all X4; proved results give only power-saving upper bounds.

ResultBoundStatus
W. C. Lu, J. Number Theory 130 (2010)E(X)X0.879Theorem
Pintz, arXiv:1804.09084 (2018)E(X)<X0.72Preprint, not peer-reviewedunpublished since 2018
Genheng Zhao, arXiv:2511.05631 (2025)E(X)=O ⁣(X7/10)Preprint, not peer-reviewedineffective constant
On ineffectivity. In the bound E(X)=O(X7/10), the constant implicit in the symbol O is ineffective: the proof provides no way to compute it, so no explicit threshold or numerical content can be extracted from it. Independently of effectivity, no bound of the shape E(X)Xθ with θ>0 — however strong — reduces the conjecture to a finite check: a power-sized exceptional set is compatible with counterexamples at every scale.

So even with E(X)=0 throughout the verified range X41018 and the power-saving bounds above, the exceptional set is still not known to be empty.

Zeros of the zeta function and density estimates

Progress in additive prime number theory is closely tied to the distribution of zeros of the Riemann zeta function. One writes N(σ,T) for the number of zeros ρ=β+iγ with βσ and γT.

Guth & Maynard — a new density estimate: Theorem

Preprint arXiv:2405.20552; published: Annals of Mathematics 203 (2026), no. 2, 623–675. The proved bound is

N(σ,T)T3013(1σ)+o(1).

This improves the long-standing exponent 12/5 of Huxley (1972), with the gain concentrated around σ=3/4 — the critical range for primes in short intervals. Such estimates are a key ingredient of modern work on primes in short intervals and, indirectly, on binary additive problems.

By itself, this estimate does not prove the Goldbach conjecture; it shifts the technical foundation on which attacks on the conjecture are built.

Conditional “doors” to Goldbach

There are precise conditional implications: certain (themselves unproved) hypotheses on the distribution of primes already imply binary Goldbach. The cleanest known formulation is due to Huang & Li, preprint arXiv:2005.03811 (2020): Conditional result

If the Elliott–Halberstam conjecture and its Möbius-twisted variant hold with distribution levels whose sum exceeds 1, then the binary Goldbach conjecture follows for all sufficiently large even integers (the implication by itself does not cover small cases, and its threshold is not effective).

This is a conditional result: both premises remain unproved. The best unconditional distribution levels (the Bombieri–Vinogradov theorem gives level 1/2) do not yet add up to the required sum.

What remains

To summarize: the conjecture has been verified up to 41018, but verification is not proof. Chen’s theorem gives (1 + 2); the Li–Liu preprint claims (1 + 1.9); the case (1 + 1) has not been reached. Exceptional-set estimates show that counterexamples are “few”, not that there are none — and the strongest of them carries an ineffective constant. Conditional results turn Goldbach into a consequence of other unproved hypotheses: the door is marked, but the keys are still missing.

The fundamental reason the sieve stalls one step short of the goal is the parity barrier: classical sieve methods cannot in principle distinguish integers with an even number of prime factors from those with an odd number. A detailed discussion of this and other obstacles is given in a separate section: The parity barrier.